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    function
    <ranges>

    std::ranges::subrange::next

    [[nodiscard]]
constexpr subrange
  next(iter_difference_t<I> n = 1) const &
    requires forward_iterator<I>;            // (1) C++20
constexpr subrange
  next(iter_difference_t<I> n = 1) const &
    requires forward_iterator<I>;            // (1) C++26

[[nodiscard]]
constexpr subrange
  next(iter_difference_t<I> n = 1) &&;       // (2) C++20
constexpr subrange
  next(iter_difference_t<I> n = 1) &&;       // (2) C++26

    概要

    先頭を前進させたsubrangeを得る。

    効果

    (1)

    auto tmp = *this;
tmp.advance(n);
return tmp;

    (2)

    advance(n);
return std::move(*this);

    例

    #include <ranges>
#include <iostream>

template<std::ranges::range R>
void print(const R& r) {
  for (int x : r) {
    std::cout << x << ',';
  }
  std::cout << '\n';
}

int main()
{
  constexpr int a[] = {1, 2, 3, 4, 5};
  std::ranges::subrange sub(a + 1, a + 4);

  print(sub);
  print(sub.next());
  print(sub.next().next());
}

    出力

    2,3,4,
3,4,
4,

    バージョン

    言語

    • C++20

    処理系

    参照