string_type str(size_type sub = 0) const;
概要
指定されたサブマッチが指す文字列を返す。
要件
ready() == true
戻り値
string_type((*this)[sub])
例
#include <iostream>
#include <regex>
int main()
{
const char s[] = " abc 0123 defgh ";
const std::regex re("(\\w+) (\\d+) (\\w+)");
std::cmatch m;
if (std::regex_search(s, m, re)) {
std::cout << "str() = '" << m.str() << "', length() = " << m.length() << std::endl;
for (std::size_t i = 0, n = m.size(); i < n; ++i) {
std::cout << "str(" << i << ") = '" << m.str(i) << "', length(" << i << ") = " << m.length(i) << std::endl;
}
} else {
std::cout << "not match" << std::endl;
}
}
xxxxxxxxxx
#include <iostream>
#include <regex>
int main()
{
const char s[] = " abc 0123 defgh ";
const std::regex re("(\\w+) (\\d+) (\\w+)");
std::cmatch m;
if (std::regex_search(s, m, re)) {
std::cout << "str() = '" << m.str() << "', length() = " << m.length() << std::endl;
for (std::size_t i = 0, n = m.size(); i < n; ++i) {
std::cout << "str(" << i << ") = '" << m.str(i) << "', length(" << i << ") = " << m.length(i) << std::endl;
}
} else {
std::cout << "not match" << std::endl;
}
}
出力
str() = 'abc 0123 defgh', length() = 14
str(0) = 'abc 0123 defgh', length(0) = 14
str(1) = 'abc', length(1) = 3
str(2) = '0123', length(2) = 4
str(3) = 'defgh', length(3) = 5
バージョン
言語
- C++11
処理系
- Clang: 3.0 ✅, 3.1 ✅, 3.2 ✅, 3.3 ✅, 3.4 ✅, 3.5 ✅, 3.6 ✅
- GCC: 4.9.0 ✅, 4.9.1 ✅, 5.0.0 ✅
- ICC: ??
- Visual C++: ??